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1022. Digital Library (30)(字符串分割) 模拟
阅读量:4072 次
发布时间:2019-05-25

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1022. Digital Library (30)

时间限制
1000 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query from a reader, you are supposed to output the resulting books, sorted in increasing order of their ID's.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=10000) which is the total number of books. Then N blocks follow, each contains the information of a book in 6 lines:

  • Line #1: the 7-digit ID number;
  • Line #2: the book title -- a string of no more than 80 characters;
  • Line #3: the author -- a string of no more than 80 characters;
  • Line #4: the key words -- each word is a string of no more than 10 characters without any white space, and the keywords are separated by exactly one space;
  • Line #5: the publisher -- a string of no more than 80 characters;
  • Line #6: the published year -- a 4-digit number which is in the range [1000, 3000].

It is assumed that each book belongs to one author only, and contains no more than 5 key words; there are no more than 1000 distinct key words in total; and there are no more than 1000 distinct publishers.

After the book information, there is a line containing a positive integer M (<=1000) which is the number of user's search queries. Then M lines follow, each in one of the formats shown below:

  • 1: a book title
  • 2: name of an author
  • 3: a key word
  • 4: name of a publisher
  • 5: a 4-digit number representing the year

Output Specification:

For each query, first print the original query in a line, then output the resulting book ID's in increasing order, each occupying a line. If no book is found, print "Not Found" instead.

Sample Input:
31111111The Testing BookYue Chentest code debug sort keywordsZUCS Print20113333333Another Testing BookYue Chentest code sort keywordsZUCS Print220122222222The Testing BookCYLLkeywords debug bookZUCS Print2201161: The Testing Book2: Yue Chen3: keywords4: ZUCS Print5: 20113: blablabla
Sample Output:
1: The Testing Book111111122222222: Yue Chen111111133333333: keywords1111111222222233333334: ZUCS Print11111115: 2011111111122222223: blablablaNot Found
 
AC代码
#include
#include
#include
#include
using namespace std;struct Node{ string ID;};vector
StrSplit(string str,char ch){ vector
result; int pos = 0; for (int i=0; i
allBooks;bool cmp(int a,int b){ return allBooks[a].ID
> authorMap,keyWordMap,titleMap,publisherMap,yearMap; string title,author,keystr,publisher,year,query; vector
curKeys; allBooks.resize(N); for(int i=0;i
keys = StrSplit(keystr,' '); for (int j=0; j
res; switch (kind) { case 1: res.assign(titleMap[query].begin(),titleMap[query].end()); break; case 2: res.assign(authorMap[query].begin(),authorMap[query].end()); break; case 3: res.assign(keyWordMap[query].begin(),keyWordMap[query].end()); break; case 4: res.assign(publisherMap[query].begin(),publisherMap[query].end()); break; case 5: res.assign(yearMap[query].begin(),yearMap[query].end()); break; } if (res.size()==0) printf("Not Found\n"); else{ sort(res.begin(),res.end(),cmp); for (int j=0; j

转载地址:http://lmhji.baihongyu.com/

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